Chemistry, asked by parthkhetre76, 11 months ago

-The wave number of a spectral line is 5 x 10^5 m-l. The
energy corresponding to this line will be
(a) 3.39 10-23 kJ - (b) 9.93 × 10-23 kJ
(c) 3.45 x 10-24 J
(d) none of these

Answers

Answered by Varsha2711

Answer:

(b) 9.93 x 10^-23 KJ..................

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Answered by abdul9838

$<b> <body \: bgcolor = "yellow">$

$\bf \green{hey \: user \: here \: is \: answer} \\ \\ \bf \green{ \huge \: solution} \\ \\ \bf \red{ \underline{ \underline{according \: to \: the \: question}}} \\ \\ \: \bf \green{wavelength{ (\lambda}) = 5 \times {10}^{5}{m}^{ - 1} } \\ \\ \bf \green{speed \: of \: light \: (c) = 3 \times {10}^{8} \: m \: per \: s }\\ \\ \bf \green{h = 6.626 \times {10}^{ - 34 \: j s} } \\ \\ \bf \pink{now} \\ \\ \bf \pink{by \: using \: formula} \\ \\ \bf \green{energy(e) = \frac{hc}{ \lambda} } \\ \\ \bf \green{e = \frac{6.626 \times {10}^{ - 34} \times 3 \times \cancel {10}^{8} }{5 \times \cancel{10}^{5} } } \\ \\ \bf \green{e = \frac{6.626 \times {10}^{ - 34} \times 3 \times {10}^{3} }{5} } \\ \\ \bf \green{e = \frac{6.62 \times \cancel30 \times {10}^{ - 32} }{ \cancel5} } \\ \\ \bf \green{e = 6.62 \times 6 \times {10 }^{ - 32} } \\ \\ \bf \green{e = 39.72 \times {10}^{ - 32} } \\ \\ \bf \green{3.97 \times {10}^{ - 31 \: j} }$

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-The wave number of a spectral line is 5 x 10^5 m-l. Theenergy corresponding to this line will be(a) 3.39 10-23 kJ - (b) 9.93 × 10-23 kJ(c) 3.45 x 10-24 J(d) none of these​

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-The wave number of a spectral line is 5 x 10^5 m-l. The
energy corresponding to this line will be
(a) 3.39 10-23 kJ - (b) 9.93 × 10-23 kJ
(c) 3.45 x 10-24 J
(d) none of these