The wavelength of a certain line in balmer series is observed to be 434.1 nm.To what value of n does it correspond
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Explanation:
The so-called Lyman series of lines in the emission spectrum of hydrogen corresponds to transitions from various excited states to the n = 1 orbit. Calculate the wavelength of the lowest-energy line in the Lyman series to three significant figures.
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When an electron jump from n = 5 to n = 2 then the radiation which emitted by electron its wavelength is observed to be 434.1 nm...
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