Question

The wavelength of a photon (in nm) having energy 3.083 × 10^12 J is .......​

Answer 1

Answer:

6.4515⋅10−29nm

Explanation:

The energy of a photon is the frequency multiplied by the Planck constant; E=hf, and the wavelength of a wave is its speed divided by it's frequency; v=fλ⇒f=vλ, so it's energy, E=hvλ. This rearranges to λ=hvE, where h is the Planck constant, v is the speed of light, and E is the energy of the photon ∴λ=6.63⋅10−34⋅3.0⋅1083.083⋅1012=6.4515⋅10−38m

=6.4515⋅10−29nm

I guess that you meant to write 3.083⋅10−12 not 3.083⋅1012, seeing as gamma rays have a wavelength of ~10−11m, which is ~10−18 times larger. 

If E=3.083⋅10−12J, using the same method, it would give a wavelength of