find the multiplicative inverse of 2+3i/3-2i
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Multiplicative inverse of (i+1)(i+2)/(i-1)(i-2)
i aslo asked this question can u plzz help
yes sure wait
that question is being answered by many users so i cannot answer as many are answering
Answered by
28
Answer: -i
Step-by-step explanation:
z= 2+3i / 3-2i
1/z = 3-2i / 2+3i
1/z = 3-2i (2-3i) / 2^2-(3i)^2
1/z = 6-9i-4i-6 / 4+9
1/z = -13i / 13
1/z = -i
Hope it helps
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