Question

The wavelength of radiation is l₀ when an electron jumps from third to second orbit of hydrogen atom. For the electron to jump from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be
(a) $\frac{16}{25}\lambda_{0}$
(b)$\frac{20}{27}\lambda_{0}$
(c) $\frac{27}{20}\lambda_{0}$
(d) $\frac{25}{16}\lambda_{0}$

Answer 1

This is your answer .(C) is the correct answer.Please I request u to mark it as the Best answer .Also I joined only today .For more queries ask me.....