The wavelength of the first line in the balmar serues is 656 nm. Calculate the wavelength of the second line and limitibg line in balmar series.
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limiting line means zero......
so
finally it's wavelength will be
WL=WAVE LENGTH
R=RIDBERGS CONSTANT
n1=2nd line
n2= limiting line
1/WL=R×Z^2(1/n1^2 - 1/n2^2)
1/WL=R×1×(1/2^2)
1/WL=R×1/4
WL=4/R
so
finally it's wavelength will be
WL=WAVE LENGTH
R=RIDBERGS CONSTANT
n1=2nd line
n2= limiting line
1/WL=R×Z^2(1/n1^2 - 1/n2^2)
1/WL=R×1×(1/2^2)
1/WL=R×1/4
WL=4/R
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