Question

The wavelength that produces a line, B in Brackett series is 2165.6 nm. Determine the transition that forms the line B.​

Answer 1

Answer:

Correct option is

B

0.162

Wavelength for the transition from n

2

to n

1

is given by

λ

1

=R(

n

1

2

1

−

n

2

2

1

)Z

2

For first line of Balmer series , n

1

=2 and n

2

=3

∴

λ

1

1

=R(

2

2

1

−

3

2

1

)Z

2

⟹λ

1

=

RZ

2

7.2

For first line of Brackett series , n

1

=4 and n

2

=5

∴

λ

2

1

=R(

4

2

1

−

5

2

1

)Z

2

⟹λ

2

=

RZ

2

44.44

∴

λ

2

λ

1

=

RZ

2

7.2

×

44.44

RZ

2

=0.162

Answer 2

correct answer is b 0. 162 wavelength for the transition from n 2 to n 1 is given by Z 2 for first line of balmer searies is 2165.6nm.