Question

The waves of 600micro m wave length are incident
normally on a slit of 1.2mm width. The value of
diffraction angle corresponding to the first minima
will be in radian):
(1)pi/2
(2)pi/6
(3)pi/3
(4)pi/4​

Answer 1

Answer:

Explanation:

dsinx=nlamda/2

n=1

1.2/1000 sinx=0.5*600/1000000

sinx=30

pi/6