Question

the weight of 5.6 litre of unknown gas is 11g calculate the gram molecular weight​

Answer 1

Answer:

What is the molecular mass of 5.6 liters of a gas at STP of 8 gram?

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While the term molecular mass is probably more correct, normally people use the term molecular weight. So the question being asked is what is the molecular weight of a gas that occupies 5.6 L under STP and weighs 8 grams? To solve use the idea gas law equation:

PV = nRT

where P is pressure (1 atm under STP conditions), V is volume (5.6 L), n is the number of moles which is equal to wt/molecular weight (MW) = 8/MW (and we are trying to find MW). R is the gas constant (here = 0.082) and T is temperature (273.15 K under STP conditions). So putting the numbers in gives:

1 * 5.6 = 8/MW * 0.082 * 273.15

Rearranging to solve for MW gives

MW = (8 * 0.082 * 273.15)/(1 * 5.6) = 31.998

This molecular weight is pretty good for oxygen though the question did not ask what the gas might be. Still, getting an answer that could represent reality leads one to think they may have done the problem correctly.

Explanation:

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Answer 2

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➳ Weight of 5.6L of unknown gas = 11g

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to find gram molecular weight of gas.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

➝ The mass of one mole of substance in grams is called its gram molecular weight.

➝ Volume of 1mol gas at STP = 22.4L

Therefore,

⟶ Mole of gas = 5.6/22.4 = 0.25

◈ Molecular weight :

⟶ Mw = weight/mole

⟶ Mw = 11/0.25

⟶ Mw = 44g/mol