The weight of a body is 400 newton on the surface of the earth at what height from the earth's surface will the weight of the body be 100 newton?pls answer
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(GM1M2)/(r)^2 = 400
GM1M2 = 400 r^2 -------(i)
where G is the gravitational constant, M1 is the mass of Earth, M2 is the mass of that object ,
and r is the radius of Earth.
let the increased height be h
GM1M2 ÷ ( r + R)^2 = 100
GM1M2 = 100 (r+R)^2 --------(ii)
as (i) = (ii)
so,
100 (r + R)^2 = 400r^2
(r + R)^2 = 4 r^2
(r+R)^2 ÷ r^2 = 4
{(r + R) /(r)}^2 = 4
( r + R) / r = 2
r + R = 2r
R = 2r-r
R = r
so,
the height is equal to the radius of earth i.e 6.4 × 10^6
GM1M2 = 400 r^2 -------(i)
where G is the gravitational constant, M1 is the mass of Earth, M2 is the mass of that object ,
and r is the radius of Earth.
let the increased height be h
GM1M2 ÷ ( r + R)^2 = 100
GM1M2 = 100 (r+R)^2 --------(ii)
as (i) = (ii)
so,
100 (r + R)^2 = 400r^2
(r + R)^2 = 4 r^2
(r+R)^2 ÷ r^2 = 4
{(r + R) /(r)}^2 = 4
( r + R) / r = 2
r + R = 2r
R = 2r-r
R = r
so,
the height is equal to the radius of earth i.e 6.4 × 10^6
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