Question

The weight of a person on the surface of the earth with mass 43 kg is ________ . ( g= 10 m/s ^2)​

Answer 1

Provided that:

• Mass on Earth = 43 kg
• g = 10 m/s sq.

To determine:

• Weight on the Earth

Solution:

• Weight on the Earth = 430 N

Using concept:

• Weight formula

Using formula:

• W = mg

Where, W denotes weight, m denotes mass and g denotes acceleration due to gravity.

Required solution:

»»» Weight = Mass × Acceleration due to gravity

»»» W = mg

»»» W = 43 × 10

»»» W = 430 N

»»» Weight = 430 Newton

Explore more:

$\begin{gathered}\boxed{\begin{array}{c|cc}\bf Mass&\bf Weight\\\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}&\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}\\\sf Mass \: is \: the \: matter \: constituting &\sf Force \: of \: attaraction \: of \: earth \\ \sf \: in \: a \: substance. &\sf on \: an \: object \: is \: called \: weight. \\\\\sf It \: is \: scalar \: quantity. &\sf It \: is \: vector \: quantity \\\\\sf It \: have \: magnitude \: only. &\sf It \: have \: magnitude \: \& \: direction \: both. \\\\\sf Mass \: has \: no \: direction. & \sf It \: act \: in \: downward \: direction. \\\\\sf SI \: unit \: of \: mass \: = kg & \sf SI \: unit \: of \: weight \: = Newton \\\\\sf Mass \: is \: constant \: everywhere. & \sf Weight \: isn't \: constant \: everywhere. \\\\\sf It \: doesn't \: change \: with \: location. & \sf It \: change \: with \: location. \\\\\sf Mass \: never \: be \: zero. & \sf Weight \: can \: be \: zero.\end{array}}\end{gathered}$

Answer 2

• Mass=m=43kg
• Acceleration due to gravity=g=10m/s^2

Weight of person=Force Applied

Using newtons second law

$\\ \sf\longmapsto Force=Mass\times Acceleration$

$\\ \sf\longmapsto Force=43(10)$

$\\ \sf\longmapsto Force=430N$