Question

the weight of a piece of stone when fully immersed in water is 18N and it displaces 4N of water . What is the weight of the stone in air ​

Answer 1

Answer:

The weight of stone in air = 18 N

Step-by-step explanation:

Given,

• Weight in water($W_w$) = 14 N

• Displaced water = 4 N

∴Weight in air can be determined as :

Weight in air($W_a$) = Weight in water($W_w$) + water displaces

$W_a$ = 14 N + 4  N

 ∴ Weight in air($W_a$) = 18 N

Answer 2

Answer:

Weight of a stone in water =25N

Weight of the stone when it is immersed in water =12N

So,

Magnitude of buoyant force acting on the stone

=(25−12)N

=13N