Question

the weight of a pure sample of a KCL O3 to be decomposer in order to get 0.96 o2

Answer 1

2KClO3 ➡️ 2KCl + 3O2

So,

2×122.5 gm KClO3 = 3×32 gm O2

So,

X gm of it = 0.96 O2

Hence, X = 2×122.5×0.96/3×32

= 2.45 gm KClO3.