Chemistry, asked by DCJaiysnu9991, 11 months ago

The weight of aluminium which contains same no of atoms that are present in 8g of oxygen

Answers

Answered by honey3017
14

x times of ratio b/w the atomic weight of oxygen and that of aluminium

x(atomic weight of hydrogen / atomic weight of oxygen)

= 3,764x 10(22 on head of 10) (atoms in 1gram of Oxygen)

So for 1gram of aluminium you have

(3,764x 10( 22 on head of 10) x 16/27 = 2.230 x 10 (22 on head od 10) atoms

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