Question

The weight of an empty balloon on a spring balance is W₁. The weight becomes W₂ when the balloon is filled with air. Let the weight of the air itself be w. Neglect the thickness of the balloon when it is filled with air. Also, neglect the difference in the densities of air inside and outside the balloon.
(a) W₂ = W₁
(b) W₂ = W₁ + w
(c) W₂ < W₁ + w
(d) W₂ > W₁

Answer 1

Hey Friend

Here is your answer

W2=W1. Since densities of air inside and outside ballon are identical, weight w of added air inside ballon is equal to weight w of displaced air. Spring will not register any difference as ballon will experience uplift force equal to w that exactly cancells weight of added air.

Volume of baloon is assumed unchanged, therefore volume of air displaced by baloon itself is unchanged.

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Answer 2

Answer ⇒ Option (a). and Option (c). is correct.

Explanation ⇒

Weight of the empty balloon = W₁

Weight of the balloon filled with air = W₂

Now, weight of the filled balloon should be W₁ + w as what we thinks. But balloon is immersed in an air, so there will be upthrust also.

Due to upthrust, W₂  < W₁ + w

Hence, Option (c). is correct.

Now,  Apparent weight of balloon = Original weight - Upthrust.  

W₂ = W₁ + w - w

W₂ = W₁

Hence, option (a). is correct.

Hope it helps.