The weight of lifter lift a load of 200 kgf to a height of 2m in a 5s calculate the work done and power developed by him
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Answer:
1000 watt
Explanation:
Force =mass ×gravity
F=200×10
=200N
Work done =d×f
2.5×2000=5000joule
The power developed by him
Power=w÷time taken
P=5000÷5=1000watt
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