The weight of oxygen gas liberated by the heating of 2.45 g of KClO3
Answers
Answer:
your answer is here !
Explanation:
No, the KClO3 from which the oxygen is evolved, has a mass of 2.45 g. You need to write the equation, balance it, convert 2.45 g KClO3 to mols, convert mols KClO3 to mols O2 using the coefficients in the balanced equation, then convert mols O2 to liters knowing that 22.4 L is the volume occupied by a mole of a gas at STP. USUALLY, oxygen is collected over water and that must be corrected for the vapor pressure of water; however, your problem doesn't say anything about water; therefore, I asume we don't need to worry about that.Post your work if you get stuck and we can help you through it.
Answer:
Explanation:
2KClO3 ------> 2 KCl + 302
2 × 122.5 g -----> 3 × 32 g
Weight of 02 obtained from 2.45g of KClO3
= (2.45/2×122.5)× 3 × 32
= 0.96gm