The weight of pure NaOH required to prepare 250 ml of 0.1 M solution is :
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1 liter = 8.6mls = 0.1N or 0.1M soln. 250ml = 1.575g = 0.IN or 0.05M std. soln. 250ml = 5.105g = 0.IN or 0.1M std.
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