The weigts of Divya and Himanshu ate in the ratio 5:7 . If Himanshu weighs 28 kg , find the weight of divya.
Answers
Answered by
50
let weight of divya n himanshu be 5x and 7x.
ATQ
weight of himanshu = 28 kg
= 7x = 28
= x = 28/7 = 4
= x = 4
therefore divya's weight = 5x = 5×4=20kg.ANS.
HOPETHIS WILL HELP
ATQ
weight of himanshu = 28 kg
= 7x = 28
= x = 28/7 = 4
= x = 4
therefore divya's weight = 5x = 5×4=20kg.ANS.
HOPETHIS WILL HELP
Saanvipriya:
thanks
Answered by
20
Hi friend, Here is the required answer:-
Let the common ratio be x.
Then the weight of Divya= 5x
And the weight of Himanshu =7x
And 7x= 28kg
x= 28/7= 4
Now weight of Divya= 5x= 5×4= 20 kg.
Hope this helps you...
Let the common ratio be x.
Then the weight of Divya= 5x
And the weight of Himanshu =7x
And 7x= 28kg
x= 28/7= 4
Now weight of Divya= 5x= 5×4= 20 kg.
Hope this helps you...
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