The wheel make 20 revolution in the distance of 66m find the diameter
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omega w =2πr
w=20
20=2πr
r=20/2π
r=10/π
r=10/3.14
r=3.18m
w=20
20=2πr
r=20/2π
r=10/π
r=10/3.14
r=3.18m
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