Question

The wickets taken by a bowler in 10 cricket matches are as follows:2.6.4.5,0,2,1,3,2,3 Find the
mode of the data
​

Answer 1

Answer:

1.9

Step-by-step explanation:

find mean

mean = $\frac{sum of observations}{no. of observations}$

mean = $\frac{2 + 6 + 4 + 5 + 0 + 2 +1 +3 + 2 + 3}{10}$

mean = $\frac{28}{10}$

mean = 2.8

find median

here x = even

median = $\frac{1}{2}(( \frac{n}{2}) obs + (\frac{n}{2} + 1)obs)$

n = 10

median = $\frac{1}{2} (5obs + 6obs)$

#substute the obs the from the sum

median = $\frac{1}{2} (5 + 0)$

median = $\frac{1}{2}$×5

median = 2.5

mode = 3(median) - 2(mean)

mode = 3 × 2.5 - 2 × 2.8

mode = 7.5 - 5.6

mode = 1.9