Math, asked by lucky123488, 4 months ago

The width of a circular track is 2 meters. If the radius of the outer circle is 6 meters, find the area of the track.​

Answers

Answered by ImperialGladiator
6

Answer:

Area of the track is 100.48m²

Step-by-step explanation:

Question says that,

A circle is surrounded by a track of width 2metres.The radius of the outer circle is 6metres.

Find the area of the track.

We know that,

Area of the track :

→ Area of outer circle - Area of inner circle.

Step 1 : Find the area of inner circle

Area of a circle : πr²

Here, the radius of the inner circle will be

→ 6m - 4m = 2m [follow the figure]

So, the area is

→ π • 2²

→ 4π

Step 2 : Find the area of outer circle

Where, the radius is 6m (given)

So, the area is

→ π • 6²

→ 36π

Step 3 : Find the area of the track

Area of the track :

→ 36π - 4π

→ 32π

  • Taking ‘π’ as 3.14

→ 32 • 3.14

→ 100.48m²

Attachments:
Answered by Anonymous
199

Answer :-

  • Area of the track is 100.48m²

Question says that,

  • A circle is a sorrounded by a track of width 2 metres. The radius of the outer circle is 6 metres.

Find the area of the track,

We know that

Area of the track :

→ Area of outer circle - Area of inner circle.

{\bf\underline{Step~1}} : Find the area of the inner circle.

Area of a circle = πr²

Here,

  • The radius of the inner circle will be

→ 6m - 4m = 2m {\sf{[Follow~the~figure]}}

So,

The area is

→ π

→ 4π

{\bf\underline{Step~2}} : Find the area of the outer circle.

Where,

  • The radius is 6m {\sf{(given)}}

So,

The area is

→ π

→ 36π

{\bf\underline{Step~3}} : Find the area of the track.

Area of the track :

→ 36π - 4π

→ 32π

  • Tracking 'π' as 3.14

→ 36 3.14

100.48m² \large\green{\bf{✓}}

Attachments:
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