Question

The width of a rectangle is 3m less than two times the length. If the perimeter of the rectangle is 120m, find its dimensions.

Answer 1

Answer:

length=19m

width=35m

Step-by-step explanation:

let width be b and length be l

b=2l-3

perimeter of a rectangle = 2(l+b)=120

                                        2(l+{2l-3})=120

                                       2(3l-3)=120

                                       3l-3=60

                                        3l=57

                                       l=19

therefore , width = 2l - 3

                          = 38-3

                           =  35

                length=19

Answer 2

let the length of the rectangle be as 'x'.

let the width of the rectangle be as '2x -3' respectively.

we know; perimeter if rectangle = 2(length + breadth)

so; 2(x + 2x -3) = 120 m

; 2(3x -3) = 120 m

; 6x - 6 = 120 m

; 6x = 120 + 6

; 6x = 126

therefore; x = 126÷6 = 21 m

also length = 21 m

and breadth = 2x - 3 i.e 2× 21-3

= 42 - 3 = 39 m

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