The width of a rectangle is 80cm. If the length of the rectangle is a twice the width, find the its perimeter.
Answers
Step-by-step explanation:
Given
width = 80cm
Length = 2 times of width
= 2 x 80
= 160
Perimeter = 2(l+b)
= 2(80+160)
= 2(240)
= 480 cm
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Step-by-step explanation:
Given:-
The width of a rectangle is 80cm. If the length of the rectangle is a twice the width.
To find:-
The width of a rectangle is 80cm. If the length of the rectangle is a twice the width, find the its perimeter.
Solution:-
The width of the rectangle = 80 cm
Length of the rectangle = Twice the width
=>2×80 cm
=>160 cm
Length of the rectangle = 160 cm
Perimeter of a rectangle whose length 'l' units and
width is 'w' units is 2(l+w) units
We have , l = 160 cm and w = 80 cm
=>Perimeter = 2(160+80) cm
=>P = 2(240) cm
=>P = 480 cm
Perimeter = 480 cm
Answer:-
Perimeter of the given rectangle is 480 cm.
Used formula:-
Perimeter of a rectangle whose length 'l' units
and width is 'w' units is 2(l+w) units