Math, asked by anjanasinghjhs6, 2 months ago

The width of a rectangle is 80cm. If the length of the rectangle is a twice the width, find the its perimeter.​

Answers

Answered by prudhvivarma2206
1

Step-by-step explanation:

Given

width = 80cm

Length = 2 times of width

= 2 x 80

= 160

Perimeter = 2(l+b)

= 2(80+160)

= 2(240)

= 480 cm

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Answered by tennetiraj86
0

Step-by-step explanation:

Given:-

The width of a rectangle is 80cm. If the length of the rectangle is a twice the width.

To find:-

The width of a rectangle is 80cm. If the length of the rectangle is a twice the width, find the its perimeter.

Solution:-

The width of the rectangle = 80 cm

Length of the rectangle = Twice the width

=>2×80 cm

=>160 cm

Length of the rectangle = 160 cm

Perimeter of a rectangle whose length 'l' units and

width is 'w' units is 2(l+w) units

We have , l = 160 cm and w = 80 cm

=>Perimeter = 2(160+80) cm

=>P = 2(240) cm

=>P = 480 cm

Perimeter = 480 cm

Answer:-

Perimeter of the given rectangle is 480 cm.

Used formula:-

Perimeter of a rectangle whose length 'l' units

and width is 'w' units is 2(l+w) units

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