the width of a rectangle is two/third of its length if the perimeter of the rectangle is 135cm find the dimensions of the rectangle
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Answered by
32
Let x be the length of the rectangle
Width=(2/3)x
Perimeter of rectangle =135
2(l+b)=135
2(x+(2/3)x)=135
2((3x+2x)/3)=135
2(5x/3)=135
10x/3=135
10x=135*3
x=405/10=40.5
Width=2/3*40.5=27
Lenght=40.5
Width=(2/3)x
Perimeter of rectangle =135
2(l+b)=135
2(x+(2/3)x)=135
2((3x+2x)/3)=135
2(5x/3)=135
10x/3=135
10x=135*3
x=405/10=40.5
Width=2/3*40.5=27
Lenght=40.5
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Answered by
29
so the length be x
so width = 2/3 x
so perimeter = 2(length + width)
135 = 2(x+2/3x)
5/3x × 2 = 135
x = (135 x 3) / (5 × 2)
x = 40.5 cm
so length = 40.5 cm and width = 2/3 x 40.5 = 27 cm
so width = 2/3 x
so perimeter = 2(length + width)
135 = 2(x+2/3x)
5/3x × 2 = 135
x = (135 x 3) / (5 × 2)
x = 40.5 cm
so length = 40.5 cm and width = 2/3 x 40.5 = 27 cm
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