The width of a triangle is 6 cm and it's diagonal is 10 cm. what is its perimeter
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Pythagoras (for a right angled triangle) :- the square of the hypotenuse (10 here) equals the sum of the squares of the other two sides, 6, and the unknown side.
so by examination the unknown side is 8.
area is length times width, so 8 times 6 equals 48 sq cm..
mathematically we have :- 10 x 10 = (6 x 6) + unknown x unknown,
so 100 = 36 + unknown squared
therefore unknown squared = 100 - 36 = 64
square root of 64 is 8.
area is 6 x 8 = 48
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