Question

The width of door is 40cm. If it is released by exerting a force of 2N at its edge ( away from the hinges), compute the torque produced which causes the door to open

Answer 1

Answer:

0.8 N m

Explanation:

Torque = force * ⊥ distance

No matter from where you push/pull from the edge, perpendicular distance will be same in every case.

Thus,

Torque = 2N * 40 cm

            = 2N * (40/100) m

            = 2*(0.4) N m

            = 0.8 N m

Hence the torque produced which caused the door to open is 0.8 N m.

Answer 2

Cᴏʀʀᴇᴄᴛ Qᴜᴇsᴛɪᴏɴ :-

• The width of door is 40cm. If it is released by exerting a force of 2N at its edge ( away from the hinges), Compute the torque produced which causes the door to open.

Given :-

$\sf\large\blue{↝Force \: applied = F = 2 \: N}$

$\sf\large\blue{↝Length \: of\: lever\: arm = d = 40 \: cm}$

Tᴏ Fɪɴᴅ :-

• The torque produced which causes the door to open

Sᴏʟᴜᴛɪᴏɴ :-

$\sf\large\purple{➭ Torque = 0.4m}$

(As distance amid the line of an action of force and axis of rotation is 40 cm.)

$\sf\large\purple{➭ Torque = f \times d}$

$\sf\large\purple{➭ Torque = 0.40\times 20}$

$\sf\large\purple{➭ Torque = 8 Nm}$

${\boxed{{\bf{∴Torque = 8 Nm}}}}$