Math, asked by thakurarshita653, 2 days ago

The width of hall is 3/4 of its length. If its perimeter is 56m. find the length and breadth of the hall​

Answers

Answered by SwarajBose
31

Answer:

Length = 16 cm, Width = 12 cm

Step-by-step explanation:

Let length of the hall be x, then width of the hall will be equal to \frac{3x}{4}

x+x+\frac{3x}{4}+\frac{3x}{4}=Perimeter\\\\\implies2x+\frac{3x}{2}=\frac{7x}{2}=56cm\\\\\implies x=\frac{56\times2}{7}=16cm\\\\$Length of Hall $= 16cm\\\\$Width of the Hall $=\frac{16\times3}{4}=12cm

Answered by Anonymous
1

Given,

Width of the hall is ¾ of its length.

Perimeter of the hall = 56m

To find,

Length and breadth of the hall.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

As, length is greater than the width. The hall will be rectangular.

Let, the length of the hall = x metres

So, width of the hall = x ×¾ = 3x/4 metres

Perimeter = 2 × (x+3x/4) = 2 × 7x/4 = 7x/2 metres

According to the data mentioned in the question,

7x/2 = 56

x = 56 × 2/7

x = 16

Length of the hall = 16 metres

Length of the width = 16 × ¾ = 12 metres

Hence, the length will be 16 metres and width will be 12 metres.

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