Question

The width of rectangle is 5cm and diagonal is 13cm. Find the perimeter of the rectangle

Answer 1

Step-by-step explanation:

In rectangle ABCD,

BC=5 cm

AC=13 cm

In triangle ABC,

ABC=90°

Therfore by pythagoras theorem,

AC^2=AB^2+BC^2

13^2=AB^2+5^2

169=AB^2+25

AB^2=169-25

AB^2=144

AB^2=12^2

AB=12 cm

Perimeter of reactangle ABCD

=2(AB+BC)

=2(12+5)

=2×17

=34 cm