Math, asked by Harshita62611, 10 months ago

The width of Sudha ‘s garden is 2/3 of its length if its perimeter is 40 m find its dimensions

Answers

Answered by Anonymous
21

SOLUTION

Let the length of the garden be x cm.

Width of the garden

 =  >   \frac{2}{3} x

Perimeter of the garden= 40m

=) 2(length+breadth)= 40m

 =  > x +  \frac{2}{3} x = 20 \\  \\  =  >  \frac{3x + 2x}{3}  = 20   \\ \\  =  >  \frac{5x}{3}  = 20 \\  \\  =  > 5x = 60 \\  \\  =  > x =  \frac{60}{5}  = 12

Length of the garden = 12m.

Width of the garden = 2/3× 12 = 8m

hope it helps ☺️

Answered by Anonymous
7

Given:

  • Perimeter = 40 m

To find out:

Find its dimensions

Formula used:

Perimeter = 2 (length + width)

Solution:

Let the length of the garden be x m.

Then, Width = 2x/3 m.

According to question:

Perimeter = 2 (length + width)

⇒ 40 = 2 ( x + 2x/3 )

⇒ 40 = 2x + 4x/3

⇒ 40 = 6x + 4x/3

⇒ 40 × 3 = 6x + 4x

⇒ 120 = 10x

⇒ x = 120/10

⇒ x = 12

∴ Length = x = 12 m and Width = 2x/3 = 2×12/3 = 8 m.

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