Question

(. The width of the rectangle is 2/3 of its length. If the perimeter of the rectangle is 80 cm,
Find its area.

answer
: 384 cm explain????
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Answer 1

Answer:

Step-by-step explanation:

Let the Length of the rectangle be x and width as y.

As per statement width of the rectangle is 2/3 of its length.Accordibgly

y = 2/3 × x …Eq..1

Perimeter of a rectangle = 2 (Length + width)

Perimeter is given as 80 cm.

2 (x + 2/3y) = 80

2 × x (1 + 2/3) = 80

x = 80 / [2 (1 + 2/3)]

x = 80 / (2 (5/3)

x = 80 / [10/3]

x = 3 × 80/ 10

x = 240/10

x = 24

Length of rectangle is 24 centimeter

Now calculating width as per Eq..1

y = 2/3 × x

y = 2/3 × 24

y = 48 / 3

The width of rectangle is 16

Answer 2

Answer :

Let the length of the rectangle be x.

Then, it's breadth = 2/3 of x

= 2x/3

Perimeter of rectangle= 2(length + breadth)

= 2( x+2x/3)

= 2( 3x/3 + 2x/3)

= 2( 5x/3)

= 10x/3

But perimeter= 80 cm

=> 10x/3 = 80

=> x= (80*3)/10

=> x= 24 cm

Therefore length = x= 24 cm

and breadth = 2x/3 = (2*24)/3

= 48/3 = 16 cm

Area = length*breadth

= 24 cm × 16 cm

= 384 cm² } Ans.

Hope it helps :)