Question

The wing span of an aeroplane is 36 m. If the plane is flying at 400 km/h, the e.m.f. Induced between

the wings tips is (assume V=4 10 T ×

-5 )

a) 16 V b) 1.6 V

b) 0.16 V d) 0.016 V​

Answer 1

Dear Student,

◆ Answer - (c)

EMF = 0.16 V

◆ Explaination -

# Given -

l = 36 m

v = 400 km/h = 400/3.6 m/s

B = 4×10^-5 T

# Solution -

EMF induced between tips of wings is -

EMF = B.v.l

EMF = 4×10^-5 × 400/3.6 × 36

EMF = 0.16 V

Therefore, EMF induced between wing tips is 0.16 V.

Thanks dear...

Answer 2

Answer:

0.16V

Explanation:

refer to attachment

Steps : Use formula e=Bvl

substitute values and solve

keep note of units.