the wire is in the shape of a square of side 10 cm if the wire is relented into a rectangle of length 12 cm find square or the rectangle
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Let a be the side of a square, l be the length and b be the breadth of rectangle.
As length of wire is constant, perimeter of both shapes would be same,
⇒4a=2(l+b)
⇒40=2(12+b)
⇒b=18 cm
Area of square=a2=102=100cm2
Area of rectangle=lb=12×18=216cm2
⇒ Area of rectangle is greater by 116cm
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