Question

The work done by a call in 10s to send 50C of charge through a resistor of resistance 2 ohm is.?

Answer 1

Answer:

T-10s

Q-50C

R-2ohm

I-Q/T

I-50/10-5A

From ohm's law

V-IR

V-5*2

V-10V

Now,

V-W/Q

5-w/50

w-50*5

W- 250J

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