Question

The work done by a force f=6xiN in displacing a particle from x=1 tox=2m is

Answer 1

Answer:

Given F=6x i

We know that work done =force×displacement

W=Integral (F dx)

W= integral (6x dx)

=6x²/2

=3x².

Given limits from x=1 to x=2

on applying limits we get,

=3(2²-1²)

=3(4-1)

=3(3)=9