The work done by a force f=6xiN in displacing a particle from x=1 tox=2m is
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Given F=6x i
We know that work done =force×displacement
W=Integral (F dx)
W= integral (6x dx)
=6x²/2
=3x².
Given limits from x=1 to x=2
on applying limits we get,
=3(2²-1²)
=3(4-1)
=3(3)=9
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