Question

The work done by a force of 20 new tons which displays a body 3.5 meter in the point of friction​

Answer 1

Given:-

• Force ,F = 20 N

• Displacement ,s= 3.5 m

To Find:-

• Work done ,W

Solution:-

As we know that work done is defined as the product of force and displacement.

❒• W = Fs

Where

W is the Work Done

F is the Force

s is the displacement

Substitute the value we get

→ W = 20 × 3.5

→ W = 2×35

→ W = 70 J

Therefore,the work done is 70 Joules.

Answer 2

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The work done by a force of 20 new tons which displays a body 3.5 meter in the point of friction

Answer in attachment..............