Question

The work done by electric field in carrying a point charge of 5 uC from a point A
to pointB is 10 mJ. The potential difference V, - Vis then
lira 10

Answer 1

Explanation:

W=qΔV

W=q(V

A

−V

B

)=10mJ (Given)

q(V

A

−V

B

)=10×10

−3

V

A

−V

B

=

5×10

−6

10

−2

=2000V

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