Question

The work done by the system in a cyclic process involving one mole of an ideal monoatomic gas is-50KJ/cycle.the heat absorbed by the system per cycle is

Answer 1

Answer:

-50kJ/cycle

Explanation:

Since it is a cyclic process, there is no net change in internal energy, i.e initial and final internal energies are equal.

Applying first law of thermodynamics, which, mathematically is

ΔU = Q - W

Since its a cyclic process, ΔU = 0

Therefore,

Q = W

Hence, heat absorbed is -50kJ