Chemistry, asked by buntybeesa93, 1 year ago

The work done during the expansion of a gas from a volume of 4 dm³ to 6 dm³ against a constant external pressure of 3 atm is (1 L atm = 101.32 J)
(a) – 6 J
(b) – 608 J
(c) + 304 J
(d) – 304 J

Answers

Answered by Mangwanikrish
3

B)-608J will be answer

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