Physics, asked by Deeps6802, 1 year ago

The work done in holding a weight of 40N at a height of 3m above the floor for 2s is in joules

Answers

Answered by chhavi96
4
W=fs
=40×3
=120j
And
P=w/t
P=120/2
P=60w
Answered by muscardinus
2

Answer:

Work done, W = 120 joules

Explanation:

It is given that,

Weight of the object, F = 40 N

Height, h = 3 m

Time, t = 2 s

The work done is equal to the product of force and the distance covered. Here, it is given by :

W=F\times h

W=40\ N\times 3\ m    

W = 120 joules

So, the work done in holding the weight of the object is 120 joules. Hence, this is the required solution.

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