Question

The work done in moving a Proton across two points having a potential difference of 1 volt is
1. 1.6 into 10 to the power minus 19 J
2. 6.25 into 10 to the power minus 19 J
3. 1.6 into 10 to the power 19 J
4. 6.25 into 10 to the power 19 J

Answer 1

Answer:

1

Explanation:

W=q× V

given its proton

q = 1.6×10 ^-19

V =1

so W = 1.6× 10^-19