Question

The work done in placing a charge of 8 x 10-18 coulomb
on a capacitor of capacity 100 microfarad is:
(A) 16 x 10-32 joule (B) 3.1 x 10-26 joule
(C) 4 x 10-10 joule (D)32 x 10-32 joule​

Answer 1

Answer:

Given , charge =q=8×10−18C and Capacitance =C=100μF

Here the work done is the energy stored in the capacitor. i.e,

W=Cq2=100×10−6(8×10−18)2=32×10−32J