Question

the work done in pushing a block of mass 10 kg from bottom to top of frictionless inclined plane 5m long and 3m high is

Answer 1

Work done by any force is defined by

W = F.d

here

F = force due to which work done is required

d = displacement

if force is inclined at some angle then work done is given as

$W = Fdcos\theta$

now here if we pull an object then applied force is same as weight of the object

$F = mg = 10*9.8 = 98 N$

displacement in the vertical direction = 3m

$W = 98 * 3 = 294 J$

so work done to pull an object up the inclined is 294 J

Answer 2

Work done by any force is defined by

W = F.d

here

F = force due to which work done is required

d = displacement

if force is inclined at some angle then work done is given as

now here if we pull an object then applied force is same as weight of the object

displacement in the vertical direction = 3m

so work done to pull an object up the inclined is 294 J