The work done in pushing a block of mass 10kg from top to bottom of a frictionless incline plane 5mlong and 3m high is?
Answers
Answered by
3
Work done = Force × distance.
The force acting on the block is the normal force.
Force = Mg Cos Ф
Cos = adjacent / hypotenuse
By pythagoras theorem.
Adjacent = √(5² - 3²) = √16 = 4
Cos Ф = 4/5 = 0.8
Take g = 10
F = 10 × 10 × 0.8 = 80 N
Here the distance covered is the height.
Work = 80 × 3 = 240 Joules
240 joules
Similar questions