Question

The work done in stretching a spring of spring constant 100N/m through a length of 10cm is

Answer 1

Work done = Force × length

= 100 × 0.1 × 0.1

= 1J.

Converted 10cm to m as it needs to be in MKS system.

Hope it helps!

Answer 2

The work done in stretching a spring of spring constant 100N/m through a length of 10cm is 0.5 Joules.

The formula: gives the amount of work required to extend a spring.

W = (1/2) k $x^2$

where

W is the work done,

k is the spring constant,

x represents the spring's displacement from equilibrium.

As per given information,

The displacement = 10 cm = 0.1 m, and

The spring constant = 100 N/m.

Hence, the following is the effort involved in expanding the spring:

W = $(1/2)\times(100 N/m)\times(0.1 m)^2$

W = 0.5 J

Hence, it takes 0.5 Joules of work to stretch a spring with a spring constant of 100 N/m across a length of 10 cm.

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