Question

The work done which is required the increase the area of a soap film

Answer 1

Work done in stretching the film is,
  W = S × ΔA
  where W is work done
  S is the surface tension
  ΔA is the change in area
                    given, 
                                    W =  3× 10-4 J  
                                                    ΔA = 2 (10×11- 10×6 )
  = 100 cm2 =10-2 m2
  So,
  S =  W/ Δ A
  =  3 ×10-4/10-2
  =  3 × 10-2 N/m
 
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Answer 2

the above answer is right