Physics, asked by CHAKRIKADARI3270, 2 months ago

The work fiction potassium is 2.0evwhen it is illuminated by light of wave length 3300angstroms photoelectrons emitted the stopping potential of photoelectrons is

Answers

Answered by ah525407

0

Answer:

1.7623v

Explanation:

given;

wavelength=3300angstroms

work function=2.0ev

find;

stopping potential of photoelectrons

formula;

K.E=evo

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