Question

The work function for a metal surface is 2 eV. If a
photon of energy 8 eV incident on the metal
surface, then number of electrons emitted by the
surface is
(a) 4 (b) 1 (c) 3 (d) 0
with explaination

​

Answer 1

answer : option (c) 3 .

Given, work function for a metal surface, Φ = 2 eV

energy of a photon incident on the metal, E = 8 eV

from photoelectric effect,

K.E = E - Φ

= 8 eV - 2 eV

= 6 eV

we know, work function of a metal is the minimum amount of energy required to remove an electron from the metal.

so, number of electrons emitted by the surface = K.E/Φ

= 6eV/2eV

= 3

hence option (c) is correct choice.

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Answer 2

$\huge\bold\purple{Answer:-}$

$\bf\large\underline\green{(c) 3}$