Chemistry, asked by MisSunshine, 11 months ago

the work function for Caesium atom is 1.9 eV. Calculate the threshold wavelength.

given 1eV=1.6×10 to the power of -19​

Answers

Answered by MANAS002
2

Explanation:

We know,

work function = Plancks constant ( h ) × threshold frequency

threshold wavelength = hC/ work function

= [ ( 6.626 × 10^-34 ) × ( 3×10^8 ) ] ÷ ( 1.9 × 1.6 × 10^-19 )

threshold wavelength = 6.53 × 10^-7 m.

Answered by kambleamit303
1

Answer:

here is formula w=hVzero wher h is plank constant which value is 6.626x10power of -34 and Vzero is work function

Explanation:

if you rearrange the formula you will get threshold wavelength Vzero=w/h if you put value

=1.9X1.6x10 power of -19/6.626X10-34

=3.04x10power 15/6.626

=0.458x 10 power 15 hz or 4.58 10 power of 16hz

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