the work function of a certain metal is 2.3eV if light of wave number 2*10^6 falls on it the kinetic energy of fastest and slowest ejected electron will be respectively
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I got KE ...but how to get min kE and max?
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5
Answer:
0.18eV , 0eV
Explanation:
K.E.min = 0 (always)
Wave no. is inversely proportional to λ
h/e = 4.15×10^-15
K.E.max = hc/λ - ϕ
= [4.14×10^-15 × 3×10^8 ×2×10^6 ] - 2.3
= 2.48 - 2.3 = 0.18
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